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THE UNIVERSITY OF AKRON
Mathematics and Computer Science
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Lesson 5: Expansion
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Table of Contents
Begin Lesson 5
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IamD S
N Z Q R C
a 3 a 4 = a 7 ( ab ) 10 = a 10 b 10
( ab − (3 ab − 4))=2 ab − 4
( ab ) 3 ( a 1 + b 1 )=( ab ) 2 ( a + b )
( a − b ) 3 = a 3 3 a 2 b +3 ab 2 − b 3
2 x 2 3 x − 2=(2 x + 1)( x − 2)
1
2 x +13=0 = ⇒ x = 26
G= { ( x, y ) | y = f ( x ) }
f ( x )= mx + b
y = sin x
Copyright c 1995–2000 D. P. Story
Last Revision Date: 8/19/2000
 
Lesson 5: Expansion
Table of Contents
5. Expansion
5.1. General Methods of Expansion
Special Products Radicals Revisited
5.2. The Binomial Formula
The Binomial Expansion Algorithm
5. Expansion
In this lesson we discuss and illustrate methods of expanding a prod-
uct of algebraic expressions. Initially, we discuss General Methods
of Expansion . Following that, we consider the problem of computing
powers of a binomial. Such expansion can be carried out quicklyand
quietlybyusing the Binomial Formula .
The student will find these techniques to be invaluable tools in their
studyof algebra, calculus, and beyond ... perhaps into an engineering
discipline.
5.1. General Methods of Expansion
In Lesson 4 , in the section entitled The Distributive Law ,we
looked at products of the form a ( b + c ) and saw that
a ( b + c )= ab + ac.
(1)
When read from left-to-right, the formula is a rule for expanding a
product. When read from right-to-left, the above formula can be used
for simple factoring or combining of similar terms.
Section 5: Expansion
In this lesson we take up the problem of expanding more complicated
expressions than we considered in Lesson 4 . These more complicated
products are products in which both factors are the sum of several
terms: such as ( x 2 +2)(3 x− 4), ( a + b )( a + b + c ), or ( x +1) 2 ( x +2) 3 .
An algebraic expression consisting of exactlytwo terms is called a
binomial . Consider the problem of computing the product of two bi-
nomials: ( a + b )( c + d ). We can and do expand this product bythe
Distributive Law .
( a + b )( c + d )= a · ( c + d )+ b · ( c + d )
by (1)
= ac + ad + bc + bd
by (1)
Thus,
General Multiplication Rule :
( a + b )( c + d )= ac + ad + bc + bd
(2)
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Section 5: Expansion
KeyPoint. If you study the formula (2) , you can see that the product
of two binomials is the sum of all possible products obtained bytaking
one term from the first factor and one term from the second factor.
This observation is valid even when there are an arbitrarynumber
of factors in the product and an arbitrarynumber of terms in each
factor.
The above observation then eliminates the need to memorize for-
mula (2) ! Let’s go the examples.
Example 5.1. Expand and combine each of the products.
(a) ( x + 1)( x + 2)
(b) (2 w − 3 s )(5 w +2 s )
(c) (2 x − 3)( x 2 2) (d) ( a + b )( a − b )
Studythe above examples. Tryto “see” the pattern and get a “feel”
for multiplying out binomials.
Exercise 5.1. Expand and combine each of the following.
(a) (4 x − 5)(3 x + 2) (b) ( x − 2 y ) 2
(c) ( x 3 / 2 + 1)( x 1 / 2 +2)
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