P27_049.PDF
(
54 KB
)
Pobierz
Chapter 27 - 27.49
49. We use
P
=
i
2
R
=
i
2
ρL/A
,or
L/A
=
P/i
2
ρ
. So the new values of
L
and
A
satisfy
L
A
=
P
i
2
ρ
4
2
P
i
2
ρ
=
30
16
L
A
.
new
new
old
old
Consequently, (
L/A
)
new
=1
.
875(
L/A
)
old
.
Note,too,that(
LA
)
new
=(
LA
)
old
.Wesolvetheabovetwo
equations for
L
new
and
A
new
:
L
new
=
√
1
.
875
L
ol
d
=1
.
369
L
old
A
new
=
1
/
1
.
875
A
old
=0
.
730
A
old
.
=
30
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