P27_017.PDF
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57 KB
)
Pobierz
Chapter 27 - 27.17
17. The resistance of the coil is given by
R
=
ρL/A
,where
L
is the length of the wire,
ρ
is the resistivity
of copper, and
A
is the cross-sectional area of the wire. Since each turn of wire has length 2
πr
,where
r
is the radius of the coil, then
L
= (250)2
πr
= (250)(2
π
)(0
.
12 m) = 188
.
5m. If
r
w
is the radius of the
wire itself, then its cross-sectional area is
A
=
πr
w
=
π
(0
.
65
×
10
−
3
m)
2
=1
.
33
×
10
−
6
m
2
. According to
Table 27-1, the resistivity of copper is 1
.
69
×
10
−
8
Ω
·
m. Thus,
A
=
(1
.
69
×
10
−
8
Ω
·
m)(188
.
5m)
=2
.
4Ω
.
1
.
33
×
10
−
6
m
2
R
=
ρL
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