P16_001.PDF

1. (a) During simple harmonic motion, the speed is (momentarily) zero when the object is at a “turning

point” (that is, when x =+ x m or x =

x m . Toexecuteafullcycleof

the motion (which takes a period T to complete), the object which started at x =+ x m must

return to x =+ x m (which, by symmetry, will occur 0 . 25 second after it was at x =

−

x m ). Thus,

T =2 t =0 . 50 s.

(b) Frequency is simply the reciprocal of the period: f =1 /T =2 . 0Hz.

−

x m is 2 x m .Thus, x m =36 / 2=18cm.

x m ). Consider that it starts at x =+ x m and we are

told that t =0 . 25 second elapses until the object reaches x =

−