Free Energy Plans.pdf

Free-energy plans

Simple Circuit to prove free-energy exists. Also plans to show you how to build a completely

solid-state free-energy circuit! Output is over 100% efficient!

This motor consumes no charge

This is a simple experiment using a toy

motor to demonstrate the principle that

charge is not consumed but wasted in

conventional electrical circuits. You could

actually use just about any type of load

even an LED, but some people will argue

that the LED would "consume" too little

energy.

So here is the setup: C1 & C2 each consist

of (4) 10,000 uf electrolytic capacitors

hooked in parallel adding up to 40,000 uf

EACH . C1 is charged with 12.5 volts C2

got 0 volts. The key point of the experiment

is to transfer charge from C1 to C2 through the toy motor. After discharge C1 and C2 are left

with 6.25 volts EACH. Joules energy calculations rule a 50% energy loss. This incorporates the

claim energy was not equal to charge. If you can't believe that, try it on your own. Theoretically

it seems possible to pulse the current of the 6.25 v capacitors through a 1:2 transformer up to

12.5 v. Some people argued that the method of measuring the running time only was not enough

since there was no regard to the RPM. I agree on that and repeated the experiment with a 74-gr.

weight to be lifted by the motor measuring the distance of lifting. The results were different.

You'll find them further down on this page.

Step by Step procedure

1.) Calibration- Disconnect everything and charge C1 with 12.5

volts. Connect the + and - of C1 with the toy motor connectors.

Measure the running time of the motor. I got 40 seconds. You may

get different results with different motors. Now you know the

maximum running time possible to draw out of C1 with this motor.

2.) Setup everything like in the schematic to the left. S1 is open. C1

is charged with 12.5 volts. Make sure C2 is at 0 volts. From now on we're counting seconds to

try and get over the 40 seconds limit.

3.) Close S1 discharging C1 through the motor and into C2. Take proper time measurement. I

used a LCD watch getting 20 seconds of motor running time. C1 and C2 are left with 6.25 v

each.

4.) Open S1 and connect the motor across C2. Measure the running time. (I got 20 seconds)

5.) Now connect the motor across C1 and measure again the running time. (I got 20 seconds)

6.) 20 + 20 + 20 seconds make a 60 seconds running time. That's 50% gain compared to the 40

seconds at calibration step 1.

There were three discharges with the first discharge in step 3 consuming no charge. Step 4 and 5

were conventional wasting of energy because the charge is now lost.

Results of the Weight Lifting

This was just a repetition of the last setup except for measuring centimeters of weight lifting

instead of motor running time. A thread was fixed to the shaft of the motor allowing it to wind up

a 74-gr. weight. The starting voltage was 10 volts.

Calibrating in step 1 gave me 71-cm lifting.

Step 2 and 3 discharging C1 into C2 through the motor lifted the weight 50.5 cm. C1 and C2

were left with 5 volts each.

Step 4 and 5 gave me each 22-cm of lifting.

That means we went up from 71 cm to 94.5 cm - a 33% gain!

The question arises: why is it not 50% like in the first setup? I think it is because the low energy-

output of the capacitors in step 4 and 5 could hardly drive the motor due to the weight. Also in

step 2 and 3 the 10 volts were dissipating faster than during calibrating. This is due to the

buildup of the opposite voltage in C2. In conventional textbooks it is said you'll lose no charge

but energy, which is converted into heat in the connecting wires, during such a capacitor

discharge. The point is, energy calculations are made in joules. I find the joule-calculation

misleading since an electric motor is not running on joules but on amperes and volts.

Back EMF

Experiment at your own risk.

Large coils or high DC inputs may cause painful electric shocks!

The picture shows: A 10 x probe which is

reducing incoming measuring voltage for an

oscilloscope. An electric coil (~1 k ohm

resistance) from an old phone bell with buzzing

mechanics operating a contact which is made

from an old relay (coil removed). Back EMF is

what you get when an electric current stops

flowing through a coil. The more abrupt this stops the better the back-EMF.

For this experimental setup you can actually use any buzzer with an electric coil. The more

windings that are on the coil the stronger the magnetic field in (or around) the coil will be and so

will be the back-EMF. All you need to do is to build up a magnetic field and let it collapse again.

The buildup and collapse sequence should run at a frequency of 25-50 cycles/sec. That's exactly

what a buzzer is doing. Activate the buzzer with an appropriate DC power source. If you use a

AC/DC transformer make sure the load is not too heavy for it. I used an adjustable transformer.

You do need an oscilloscope for exact measurements and you should use the 10x measuring

probe if the created voltage exceeds the maximum. However if you do not own such a wonderful

instrument you might use your fingers (at your own risk). If you feel nothing, try again with wet

fingers. Forget your multi-meter, both analog and digital, because it's not going to show those

high voltage spikes.

This is the typical image of back-EMF. The

voltage spikes are more than 4 squares up,

each square means 5 x 10 volts (due to 10 x

probe). Certain tingling in fingers is felt

when touching the blank wire. If it were not

for the low amperage in this circuit the 200

volts spikes would have been dangerous

indeed. All this from a buzzer at 10 volts

and 3-4 mA(DC).

Back-EMF is what makes your spark plugs

spark. But it is also an unwanted

phenomenon in electrical engineering, for

instance in DC motors where back-EMF

causes sparking on commutators, eating up battery

power.

How might it ever be useful for free energy? We're

getting to that.

How can we use this back

EMF for free energy?

Based on the previous BACK-EMF Test, I tried the

following setup to prove a gain of charge during a

capacitor discharge (C1 into C2) through the buzzer, by

collecting the BACK-EMF of the buzzer-coil in a third

capacitor C3 (470 uf). I minimized the self-discharge of

C1 and C2 by using higher quality capacitors (4700uf). For the diode (DRR 104) you can

probably use any type. The faster the switching the less energy you'll lose. The total charge of

the system was at the start in C1 (21.5 volts). C2 and C3 were at 0 volts. After the buzzer

stopped there is still some voltage flowing from C1 into C2. It takes a few seconds until C1 and

C2 are balanced. Measurement showed C1 and C2 (11.4 volts) each! and C3 (25.2 volts). I had

the buzzer working and ended up with more charge than I started with!

These capacitor discharge experiments prove that the electrons moving through a load are not

used up but only slowed down giving some of their kinetic energy to do work in the load.

Conventional textbooks say that no charge but energy is lost in the connecting wires during such

a discharge. Then what IS the difference between energy and charge? Theoretically it should be

possible to pulse the charge in C2 through a transformer back into C1 ending up with 21.5 volts

again. The question arises: Where is the bug in energy-calculations? Is there a difference

between mechanical- and electrical power transmission?

If you want to check it out, here is the circuit.

C1 and C2 are electrolytic capacitors with 4700 uf each. C3 is

an electrolytic capacitor with 470 uf. For the diode any

universal diode with appropriate working voltage will do it. I

used (DRR 104). The buzzer is self-made from an old

telephone-ringing coil and the contacts are from an old relay.

So how can we use this to build a free energy

generator?

I believe there are 2 ways of doing

it:

• By building a Solid State

free-energy circuit

• By building a Mechanical

generator free-energy

machine

Solid state Free-energy circuit

It's very simple actually. The idea

is that we use what we have

learned from the capacitor tests to

create a circuit that uses the

capacitors to run the load and then

by discharging the 1/2 full

capacitor into a DC-DC converter

we can recharge the initial cap and start again. And have some energy left over!

Here’s how it works:

It’s very simple actually. First we charge C1 with 12 volts. Then we close S1 and discharge C1

through the motor and into C2. Now C1 and C2 are both at 6v and we got the motor to run for a

while. Now make sure S1 is open and close S2. This discharges C2 into the DC-DC converter,

which now charges C1 back to 12v. Open S2 and we can repeat it again and again.... And we

now have Free energy! Then we just need to build a circuit to replace the manual switches.

Free-energy generator (mechanical)

Well we have already proven that we have free energy available from doing the capacitor tests,

now we need to come up with a way to convert that extra energy to be used in a closed loop

system ie.. to charge a battery maybe. The problem with close looping it with a battery is that it

is difficult to tell if the machine is running over 100% efficiency. Therefore I propose we use

large capacitor banks. This way we can start the device with a battery and once it is up to speed,

we disconnect the battery and let the capacitors do the rest. We will know if it's running over

unity right away if it doesn’t stop within a minute or so.

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