p19_109.pdf

(66 KB) Pobierz
Chapter 19 - 19.109
109. (a) The8 . 0cmthicklayerofairinfrontoftheglassconductsheatatarateof
P cond = kA T H
T C
=(0 . 026)(0 . 36) 15
0 . 08 =1 . 8W
L
which must be the same as the heat conduction current through the glass if a steady-state heat
transfersituationisassumed.
(b) Fortheglasspane,
P cond = kA T H
T C
L
1 . 8=(1 . 0)(0 . 36) T H
T C
0 . 005
whichyields T H
T C =0 . 024C .
 
Zgłoś jeśli naruszono regulamin