p19_109.pdf
(
66 KB
)
Pobierz
Chapter 19 - 19.109
109. (a) The8
.
0cmthicklayerofairinfrontoftheglassconductsheatatarateof
P
cond
=
kA
T
H
−
T
C
=(0
.
026)(0
.
36)
15
0
.
08
=1
.
8W
L
which must be the same as the heat conduction current through the glass if a steady-state heat
transfersituationisassumed.
(b) Fortheglasspane,
P
cond
=
kA
T
H
−
T
C
L
1
.
8=(1
.
0)(0
.
36)
T
H
−
T
C
0
.
005
whichyields
T
H
−
T
C
=0
.
024C
◦
.
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P19_001.PDF
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P19_003.PDF
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P19_005.PDF
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Inne foldery tego chomika:
chap01
chap02
chap03
chap04
chap05
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